MATH SOLVE

4 months ago

Q:
# HELLPPP! On my algebra work. please show your work, whoever shows their work gets a brainlest.

Accepted Solution

A:

y-intercept occurs at x = 0 because x = 0 is where the y-axis is.

Set x = 0 to find the y-intercept value.

the "constant multiplier" is the number that the exponent is on. it is called this because that is the repeated multiplication factor ( example: 2² = 2 · 2 and 2³ = 2·2·2 so it's a constant multiplication)

a. for y = 3 · 6^x, y-intercept is

y = 3 · 6^0

anything to power of 0 is just 1 so we're left with

y = 3 ⇒ y-intercept is 3

Constant multiplier is 6 (exponent on 6)

b. for y = 3/4 · 8^x, the y-int is

y = 3/4 · 8^0 = 3/4 ⇒ y-intercept is 3/4

Constant multiplier is 8

c. for y = 3600 · (1/2)^x, the y-intercept is

y = 3600 · (1/2)^0 = 3600 ⇒ y-intercept is 3600

Constant multiplier is 1/2

Set x = 0 to find the y-intercept value.

the "constant multiplier" is the number that the exponent is on. it is called this because that is the repeated multiplication factor ( example: 2² = 2 · 2 and 2³ = 2·2·2 so it's a constant multiplication)

a. for y = 3 · 6^x, y-intercept is

y = 3 · 6^0

anything to power of 0 is just 1 so we're left with

y = 3 ⇒ y-intercept is 3

Constant multiplier is 6 (exponent on 6)

b. for y = 3/4 · 8^x, the y-int is

y = 3/4 · 8^0 = 3/4 ⇒ y-intercept is 3/4

Constant multiplier is 8

c. for y = 3600 · (1/2)^x, the y-intercept is

y = 3600 · (1/2)^0 = 3600 ⇒ y-intercept is 3600

Constant multiplier is 1/2